ID:274490
 Mar 27 2002, 4:07 pm
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I know i spelled that wrong but does anyone know why .9 repeading is 1 because .9 repeading = .9 repeading not 1 but does anyone know this?
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Actually, in mathematics, .9 repeating (.999999999...) is equal to 1. I can't remember the exact justification for it--I believe it uses limits.
-AbyssDragon | |
AbyssDragon wrote:
Actually, in mathematics, .9 repeating (.999999999...) is equal to 1. I can't remember the exact justification for it--I believe it uses limits. Oh, *that*. I remember that, but I just accept that as an axiom. =) | |
AbyssDragon wrote:
Actually, in mathematics, .9 repeating (.999999999...) is equal to 1. I can't remember the exact justification for it--I believe it uses limits. Well there are two justifications. The first is simple common sense--that .9999... would be 1 minus 10-infinity, the latter term of which evaluates to 0. The second is algebraic. N = 0.9999.... 10N = 9.9999.... 10N-N = 9.9999.... - 0.9999.... 9N = 9 N = 1 Lummox JR | |
It's called round-off error -- it's a problem with computers themselves, not with BYOND, so there's nothing that can really be done about it. (And it's spelled "repeating". ;-) )