Declaring variables as binary

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ID:273377 Mar 9 2010, 3:03 pm
Ranch Jolly	You know how you can declare variables in oct, and hex? var/dec = 20 var/oct = 024 var/hex = 0x14 Well, I was just curious, is there a way you can declare them in binary form? This would make it slightly easier for making bitwise type stuff.

Mar 9 2010, 3:08 pm

Garthor

That's not declaring the variables as anything, it's simply interpreting the constant value differently: 024 means 24 octal and 0x14 means 14 hexidecimal. The variables store the same thing regardless.

For bitwise type stuff, there really shouldn't be a need for this. Each bit should have its own constant and you can just | constants together. Like mob/sight (SEE_SELF|SEE_TURFS) or dir (NORTH|EAST == NORTHEAST).

So, you'd want to do:

#define BLAHFLAG 1
#define BUHFLAG 2
#define BEHFLAG 4
//etc.

x = BLAHFLAG | BEHFLAG

Mar 9 2010, 3:11 pm In response to Garthor
Ranch Jolly	I meant like... #define FLAG bin-1 #define FLAG2 bin-10 It just made me curious if you could give the variables a value in dec, oct, hex, and bin. EDIT: Useless, but I just wanted to know more.

Mar 9 2010, 3:26 pm In response to Ranch Jolly
Garthor	If you really, really need to, you can use the << bit-shift operator. Though, you'd want to use a constant variable rather than a #define in that case. So, 1 in binary becomes 1 << 0, 10 becomes 1 << 1, 100 becomes 1 << 2, and so on.

Mar 9 2010, 3:31 pm In response to Garthor
Ranch Jolly	Garthor wrote: If you really, really need to, you can use the << bit-shift operator. Though, you'd want to use a constant variable rather than a #define in that case. So, 1 in binary becomes 1 << 0, 10 becomes 1 << 1, 100 becomes 1 << 2, and so on. I didn't think of that, thank you very much.