prob()

ID:267675
 
Aug 13 2003, 2:07 pm
hi

can some one give me an example of the prob() proc?

thanks
Aug 13 2003, 2:13 pm
Prob()....
well,put a number ,1 to 100, in the (). and it does Probability of that number percent.
ex:
mob
   var/wins = 0
   var/loses = 0
   var/trys = 0
   verb/Check_My_Chances()
      if(usr.trys == 10)
         usr << "[usr.wins] wins, and [usr.loses] loses"
      else
         usr.trys ++
         if(prob(50))
            usr.wins ++
            usr << "You win"
         else
            usr.loses ++
            usr << "You lose"

Chances of 50% you win, 50% you lose.
You can also use prob() in a pick() proc.
mob
   verb/Pick_Apple()
      var/apple = pick(prob(70);"Red",prob(30);"Green")
      usr << "[apple] Apple"

That makes it so you have 70% chance of Red, and 30%
chance of Green.
Aug 13 2003, 2:14 pm

<code>mob/proc/FlipCoin() if(prob(50)) usr << "Its heads!" else usr << "Its tails!"</code>

The prob() proc is basically just a percent chance of something happening. prob(50) is a 50% chance that the result will be true, while prob(25) is a 25% chance. Its a pretty simple concept.
Aug 13 2003, 2:15 pm
In response to JackGuy
thanks again jack
Aug 13 2003, 2:27 pm
In response to Foomer
thanks foomer

i am trying to use it with an area and i cant get it to work, so there is a prob(25) of getting cought and prob(50) of not getting cought

i put the area code here:

area
first_door
Entered()
prob(25)
usr << "you were not fast enough!"
prob(50)
usr << "You were lucky"


(i had to edit some of it looked confusing because they were long lines)
Aug 13 2003, 2:32 pm
In response to Mousie_kebabs
 
area
    first_door
        Entered()
            var/happen = pick(prob(25);1,prob(50),2)
            if(happen == 1)
                usr << "you were not fast enough!"
            if(happen == 2)
                usr << "You were lucky"

That should do it
Aug 13 2003, 2:36 pm
In response to JackGuy
thanks :-D
Aug 13 2003, 3:02 pm
In response to JackGuy
JackGuy wrote:
> area
>     first_door
>         Entered()
>             var/happen = pick(prob(25);1,prob(50),2)
>             if(happen == 1)
>                 usr << "you were not fast enough!"
>             if(happen == 2)
>                 usr << "You were lucky"
>

That should do it

I think theres a probleme with this, what I see is realy happening is this:
1/4 of a chance to get 1 and 1/2 of a chance to get 2, that makes out as 33.3% to get 1 and 66.6% to get 2 to form the 100% (I'm pretty sure this is what goes on but im not perfect)
Aug 13 2003, 3:05 pm
In response to FranquiBoy
Yeh, you'd have to use that (im just showing him what to do with the numbers he supplied), but it WOULD work the way i showed, but it would have a runtime error or something, for the chances it doesnt pick one.
Aug 13 2003, 3:09 pm
In response to JackGuy
pick proc
See also:
prob proc
Format:
pick(Val1,Val2,...)
Returns:
One of the given values randomly chosen.
To make a particular value more or less likely to be chosen, a relative probability may be specified like this:

prob(P); Val
Or
P; Val

A value for P of 200 makes it twice as likely as the norm, 50 half as likely, and so on.

Example:
obj/food
verb/eat()
usr << pick (
"[usr] eats \a [src].",
prob(50)
"[usr] devours \a [src].",
prob(25)
"[usr] wolfs down \a [src]."
)
del(src)

Also, to pick a value randomly from a list, simply pass the list as the sole argument into pick(). In this case, there is no provision for weighting the probabilities. All items in the list are equally likely.

This is straight from the help file and if you look at the exemple, the total odds are 175 that means they dont have to add up to 100 exacly...