Question about logic

ID:2363863
 
Apr 22 2018, 6:15 pm
Code:
mob/verb/test()
    var
        list/l = list(5)
        a=1
        n=-5
    world<<"([5 in l]/[a==1]/[n<0]) -> [(5 in l&&a==1&&n<0)]"



(1/1/1) -> 0

Problem description:
If all elements are true, when together by && or & should not be true? Is this happening because of the in, isolating it on a separate line does it work properly, should it work like this or is it some logic I do not know?
Apr 22 2018, 6:24 pm
It's an order of operations thing. You'd want to encompass the second "5 in 1" part in parenthesis.
Apr 22 2018, 6:26 pm
"in" has VERY low priority as far as operators go. What you're asking is more like 5 in (l && a == 1 && n < 0) which winds up being 5 in 1 which is false. Whenever you use the in keyword, always wrap it in () ex (5 in l) && a == 1 && n < 0.

If you think that's weird and stupid, it is.
Apr 22 2018, 7:28 pm
Thanks, this happen only in DM?
Apr 22 2018, 7:47 pm
Not many other languages have an 'in' keyword of this nature.