ID:1867725
 
Code:


Problem description:Terminate the loop with the given label. If no label is specified, the innermost loop containing the break statement is assumed. this is from the byond references. How does one do this if they need to break out of a loop that is not th inner most. I thought i got it but it just creates an infinite loop error for me, even though it should be breaking out of the loop.

nvm problem solved, silly mistake.

just in case people visit here later

if you want to do thise than

labelName:
[TAB]for(bla;bla;bla)
[TAB][TAB]break labelName