B = (int(D/4)%255) meens?

ID:183622
 
Jun 9 2007, 10:02 pm
Well just wondering how I would put this into BYOND language.

B = (int(D/4)%255)

Let me know if any of you knows, I dont know any other languages and really got no idea what to do with the "%"
And sinces this aint really BYOND language nor a code problem I've wacked it down here.

Thank you!

- Fint
Jun 9 2007, 10:09 pm
b = (round(d/4))%255
Jun 9 2007, 10:11 pm
In response to Xx Dark Wizard xX
Ah, darn I've been coding for quite some years on BYOND and just now i discover the following.

%: The remainder of A / B

Thanks for pointing me into the right direction!
Jun 9 2007, 11:51 pm
In response to Fint
It's called 'modulus'. Most programming languages with C-derived syntax (Java, C++, D, Python) would use % for that.
Jun 10 2007, 6:42 pm
In response to Jp
It's actually an extremely convenient operator once you get used to it.
Jun 13 2007, 11:11 am
In response to Rockinawsome
Rockinawsome wrote:
It's actually an extremely convenient operator once you get used to it.

Good for making random numbers in C++
Jun 13 2007, 2:24 pm
In response to Shlaklava
And other uses as well: 
if(round(rand()*100)%2)world<<"The number is odd because an even number is divisible by 2 making the remainder always 0."
Jun 13 2007, 3:44 pm
In response to Shlaklava
Good for making random numbers in any language. The Mersenne Twister is based around the whole linear-congruential-generator thing.