Just wondering...

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Feb 3 2004, 3:38 pm
In response to Jon88
Jon88 wrote:
Jerico2day wrote:
... I'm still conviced the answer lies somewhere in Pi

You're right. In fact, EVERYTHING that can be represented numerically in some form or another lies somewhere in Pi. Since Pi is totally random, any and every possible combination of digits exists in it.

Sorry to burst your bubble, but this is a mathematical fallacy. Just because Pi's digits go on infinitely without repeating doesn't mean all possible combinations of numbers will come up. Since every combination of digits is also an infinite set, the two sets don't have to overlap completely.

Lummox JR
Feb 3 2004, 3:39 pm
In response to Jon88
I just input it into my calculator. Pi=3.141592654 =P
Feb 3 2004, 3:42 pm
In response to Lummox JR
Well, if you take a hint from The Bible Code, and start applying random methods to analyze the numbers, then the number of methods you can use to analyze the numbers is also infinite, thus, you can get any sequence of numbers from pi.
Feb 3 2004, 3:43 pm
In response to Goku72
Goku72 wrote:
I just input it into my calculator. Pi=3.141592654 =P
That's more accurate, but still an approximation. Pi extends forever. The digits never end. Just like 22/7.
Feb 3 2004, 3:45 pm
In response to Jon88
Saying it's "just like" 22/7 is silly. 22/7 can be expressed as a fraction, and is thus in a completely different set of numbers than pi, which cannot.

A better comparison would be the square root of 2.
Feb 3 2004, 3:53 pm
In response to Garthor
The fact that the digits never end is what I was trying to explain was similar between the two.
Feb 3 2004, 4:19 pm (Edited on Feb 3 2004, 4:25 pm)
In response to Jon88
You could say that the digits of 2.0000000000000000000000000000000000000000... never end. It's the same digit being repeated, however, making it completely different from 3.1415926535897932384626433832795028841971693993751058209749 445923078164062862
08998628034825342117067982148086513282306647093844609550582231725359408128481 1
174502841027019385211055596446229489549303819644288109756659 334461284756482337
867831652712019091456485669234603486104543266482133936072602 491412737245870066
063155881748815209209628292540917153643678925903600113305305 488204665213841469
519415116094330572703657595919530921861173819326117931051185 480744623799627495
673518857527248912279381830119491298336733624406566430860213 949463952247371907
021798609437027705392171762931767523846748184676694051320005 681271452635608277
857713427577896091736371787214684409012249534301465495853710 507922796892589235
420199561121290219608640344181598136297747713099605187072113 499999983729780499
510597317328160963185950244594553469083026425223082533446850 352619311881710100
031378387528865875332083814206171776691473035982534904287554 687311595628638...

(shortened for various reasons).

Oh, hey, there are six nines in a row right there....
Feb 3 2004, 5:09 pm
In response to Jon88
Jon88 wrote:
Goku72 wrote:
I just input it into my calculator. Pi=3.141592654 =P
That's more accurate, but still an approximation. Pi extends forever. The digits never end. Just like 22/7.

Ah, but the digits do end in 22/7: In any base that's a multiple of 7. In other bases the digits repeat. Whenever you have a fraction of integers, which is the definition of a rational number (except of course in x/0 cases), the result is either finite or has infinitely repeating digits.

Lummox JR
Feb 3 2004, 5:24 pm
In response to Lummox JR
How many digits does it have after the decimal?
Feb 3 2004, 5:45 pm
In response to Jon88
Jon88 wrote:
How many digits does it have after the decimal?

22/7 in base 7? 1. The result in base 7 is 3.1.

Lummox JR
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