Key Restrictions at Login (moved from Newbie Central)

ID:147503
 
Apr 19 2004, 3:01 pm
How can create a list of keys that I want to allow to Login?

EX:
mob/Login()
if(!src.key=="Xallius")
del(src)

How can I implement this for multiple keys?

EX: I want to allow keys: "Xallius" and "Azen"

I know this is relatively simple and I thought that I would just use the || operator, but I can't seem to get that to work.
Thanks.
Apr 19 2004, 3:06 pm
Xallius wrote:
How can create a list of keys that I want to allow to Login?

EX:
mob/Login()
if(!src.key=="Xallius")
del(src)

How can I implement this for multiple keys?

EX: I want to allow keys: "Xallius" and "Azen"

I know this is relatively simple and I thought that I would just use the || operator, but I can't seem to get that to work.
Thanks.

mob/Login()
if(src.key!="Xallius")
del(src)

Or, for multiple keys:

mob/Login()
if(src.key!="Xallius"||src.key!="Azen")
del(src)

Apr 19 2004, 3:52 pm
In response to HavenMaster
Ok, I figured it out, thanks.
The coding you sent just needed the || replaced with &&.

with &&
"If the key is not Xallius or Azen, delete them"

opposed to:
with ||
"If the key is not both Xallius and Azen, delete them"
Apr 19 2004, 4:08 pm
In response to Xallius
An even easier way would be
if(!(key in list("Xallius","K1","K2","K3"))
    return
Apr 19 2004, 4:55 pm
In response to Xallius
Actually

|| = OR

&& = AND
Apr 20 2004, 2:45 pm
In response to Nadrew
But in this instance.......

mob/Login()
if(src.key!="Xallius"&&src.key!="Azen")
del(src)
The && will allow a key if it is either Xallius or Azen,
where as....

mob/Login()
if(src.key!="Xallius"||src.key!="Azen")
del(src)
This would only allow a key that was both Xallius and Azen..
Impossible =)

You have to think of what it would do logically instead of the definition of the operators.
Apr 20 2004, 2:46 pm
In response to sapphiremagus
Thanks. That should save me some typing. =)
Apr 21 2004, 11:18 am
In response to Xallius
Right-o.

if(foo != bar && foo2 != bar2)

is equivalent to

if(!(foo == bar || foo == bar2))

What you want is a foo that is neither bar nor bar2, so or makes sense, but you distributed the not across the equation so it switches the or to an and.
Apr 21 2004, 12:42 pm
Apr 21 2004, 12:58 pm
In response to XzDoG
This really isn't the best way to solve this problem. Any time you want to change the list, you have to recompile the game and restart it. If you're seeding copies to trusted testers/hosts, you have to make sure they all update their copies. It can easily turn into a logistical nightmare.

Instead, simply create a hub entry with distribution by invitation only. Go to the subscribers list and add/delete anyone you want, any time you want. In your code, do something like this:
client/New()
    if (!src.CheckPassport("yourpassportstring"))
        world.log << "[src] tried to access the game."
        del(src)
    . = ..()


You'll never have to update this piece of code again.