Code:
Problem description:
I'd like to grab a list of colors from an icon. is there a simpler way than looping through each pixel and icon state and grabbing all of the colors in the image?
Jul 6 2015, 12:23 am
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Kaiochao
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Nope. Why?
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How does DM list all the colors of an icon? It seems like there's some sort of reference to it somewhere.
It's useful for icon editting, for instance if i have an image with 30+ colors and I want to change all the colors to the same value. Or if I want to swap colors out - various things. | |
DM cheats; since it can load up the icon, it can just look at the direct data. There's no internal function for getting a list of colors, although I can see the value in one.
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I remember when I requested GetPixel() back in the day and was sad when it didn't come with SetPixel() (but DrawBox() worked so I was happy again). I posited the idea that calling the proc with no arguments would cause it to return a list of colors used in the icon with the format being something like
list("[x],[y]"="#RRGGBBAA") but it was ultimately decided that the format was pretty unfriendly and the conversation didn't really go too far beyond that. I'd definitely love a quick way to grab all of the colors myself. Calling GetPixel() recursively is slooooow. | |
Another question, is it possible to Grab a certain section of an image?
For instance, by color-  like in this image- if i wanted to grab each green block by it's SW and NE corners based on the color i found as i looped through each pixel. Then copy that space - what apsects of DM would i look at in order to get started on doing that? | |
what apsects of DM would i look at in order to get started on doing that?* Nested for() loops, to go over every pixel * Working with the /icon datum: * * icon() to load up your sheet * * icon.GetPixel() to check the color of each pixel * * icon.Crop() to change the icon to a certain rectangle of it * * icon.Insert() to insert your cropped frames into an icon | |
It seems I've already got 1/2 of that coded then.
Well, a little more than half. Just need to work out the details. | |